simplify (c^2+4c)/(c^2-4)*(c-2)/(3c+12)

⚠ 4c is read as the product 4*c: for a power, write 4^c

⚠ 3c is read as the product 3*c: for a power, write 3^c

The original denominators must be nonzero:

c \in ℝ \ {-4, -2, 2}

Let's reduce:

\frac{c^{2} + 4 c}{c^{2} - 4} \cdot \frac{c - 2}{3 c + 12}

Let's factor in

ℝ

c^{2} + 4 c

You can factorize this expression into:

c \cdot (c + 4)

We divide

\frac{c + 4}{3 c + 12}

by the common factor:

c + 4

, which gives the new fraction:

\frac{1}{3}

Using the formula:

a^{2} - b^{2} = (a - b) \cdot (a + b)

, we divide

\frac{c - 2}{c^{2} - 4}

by the common factor:

c - 2

, which gives the new fraction:

\frac{1}{c + 2}

\frac{c}{(c + 2) \cdot 3}

▶Simplified form:

\frac{c}{3 \cdot (c + 2)}