simplify (-2+i)/(6-10i)
1) Let's reduce: -2 + i6 -10i
ⓘ To make the denominator real, multiply the numerator and denominator by its conjugate, since (a+bi)(a-bi) = a²+b²: -2 + i6 -10i = (-2 + i)×(6 + 10i)62 + (-10)2
(-2 + i)×(6 + 10i)62 + (-10)2
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 62 = 6×6 = 36, (-10)2 = (-10)×(-10) = 100
(-2 + i)×(6 + 10i)36 + 100
ⓘ The numerator and the denominator are computed before the division: 36 + 100 = 136
(-2 + i)×(6 + 10i)136
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: (-2 + i)×(6 + 10i)136 = (-2 + i)×(3 + 5i)68
(-2 + i)×(3 + 5i)68
ⓘ Expand by multiplying each term inside the parentheses: (-2 + i)×(3 + 5i) = -2×3 -2×5i + i×3 + i×5×i
-2×3 -2×5i + i×3 + i×5×i68
ⓘ Multiplications are done before additions and subtractions: 2×3 = 6, 2×5 = 10■Multiplying powers with the same base adds the exponents: i×i = i2
-6 -10i + i×3 + 5i268
ⓘ Like terms are grouped by adding their coefficients: -10i + i×3 = -7i■Multiplying by -1 gives the opposite: 5×(-1) = -5■i^2 = -1, so the powers of i reduce to 1, i, -1 or -i: i2 = -1
-6 -7i -568
ⓘ The minus sign is factored out, changing the sign of each term: -6 -7i -5 = -(6 + 7i + 5)
-6 + 7i + 568
ⓘ The numerator and the denominator are computed before the division: 6 + 5 = 11
-11 + 7i68
ⓘ A complex number is written in algebraic form a + b*i, a being its real part and b its imaginary part: -11 + 7i68 = -1168 -768×i
▶Simplified form:   -1168 -768×i
2) The numeric value of: -1168 -768×i is:
▷ -≈ 0.1618 -≈ 0.1029i