simplify (x^3-x)/x
The original denominators must be nonzero: x ≠ 0
Let's simplify: x3 -xx
Let's factorize in ℝ: x3 -x
You can write the expression in factored form: x·(x2 -1)
⇥Let's factor in ℝ: (x2 -1)
⇥For x2 -1, we recognize a difference of two squares: x2 -12. Apply a2 -b2 = (a -b)·(a + b), with a = x and b = 1
⇥ⓘ The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor: x3 -xx = (x + 1)·(x -1)
⇥Factors identified: (x + 1)·(x -1)
ⓘ Expand by multiplying each term inside the parentheses: (x + 1)·(x -1) = x·x + x·(-1) + 1·x + 1·(-1)
x·x + x·(-1) + 1·x + 1·(-1)
ⓘ Multiplying powers with the same base adds the exponents: x·x = x2■Multiplying by -1 gives the opposite: x·(-1) = -x
x2 -x + x -1
ⓘ Like terms are grouped by adding their coefficients: -x + x = 0
x2 + 0 -1
ⓘ Adding 0 changes nothing: 0 -1 = -1
▶Simplified form:   x2 -1