solve cos(x)=0 on [0,2*pi]
Let's solve in ℝ: cos(x) = 0
cos(θ) = 0 means that: θ = π2 + kπ, k ∈ ℤ
Solution found: x = π2 + kπ
For x = π2 + kπ, 0 ≤ k ≤ 1. In [0, 2π], we keep the solutions lying in the interval: { π2, 3π2 }
▶Solution:   x = { π2, 3π2 }
The numeric value of: x = { π2, 3π2 } is:
x = { ≈ 3.14162, ≈ 3·3.14162 }
x = { ≈ 1.5708, ≈ 9.42482 }
▷ x = { ≈ 1.5708, ≈ 4.7124 }