Let's solve in ℝ: ex = 1 Let's apply the ln function on both sides: ln(ex) = ln(1) ⓘ For real x, ln(exp(x)) = x; wherever ln(x) is defined, exp(ln(x)) = x: ln(ex) = x■ln(1) = 0, since exp(0) = 1: ln(1) = 0 ▶Solution obtained: x = 0
