solve sin(x)=0 on [0,2*pi] — step-by-step solution

Let's solve in

ℝ

\sin (x) = 0

sin(θ) =

0

is equivalent to: θ =

k π

, k ∈ ℤ

Solution found:

x = k π

For

x = k π

0 \leq k \leq 2

. In

[0, 2 π]

, we keep the solutions lying in the interval:

{0, π, 2 π}

▶Solution:

x = {0, π, 2 π}

The numeric value of:

x = {0, π, 2 π}

is:

x = {0, \approx 3.1416, \approx 2 \cdot 3.1416}

▷

x = {0, \approx 3.1416, \approx 6.2832}