Let's solve in ℝ: x2 -5x + 6 = 0 Given the quadratic form ax2 + bx + c, let's compute the discriminant: Δ = b2 -4ac Δ = (-5)2 -4·1·6 Δ = 25 -4·6 Δ = 25 -24 Δ = 1 Since Δ > 0, the equation has two solutions: Solution first: -b -Δ2a x1 = 5 -12 x1 = 42 x1 = 2 For the 2nd solution, we obtain: -b + Δ2a x2 = 5 + 12 x2 = 62 x2 = 3 Solution found: x = 2 Solution obtained: x = 3 ▷Answer: x = { 2, 3 }