solve x^2+x-6=0
Let's solve in : x2 + x -6 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac
Δ = 1 -4·1·-6
Δ = 1 -4·-6
Δ = 1 + 24
Δ = 25
As Δ > 0, the equation has two solutions:
Solution first: -b -Δ2a
x1 = -1 -252
x1 = -1 + 52
x1 = -62
x1 = -3
For the 2nd solution, we obtain: -b + Δ2a
x2 = -1 + 252
x2 = -1 + 52
x2 = 42
x2 = 2
Solution obtained: x = -3
Solution obtained: x = 2
Result:   x = { -3, 2 }