sum(1/n^2, n=1, +inf) — step-by-step solution

Let's evaluate:

\sum_{n = 1}^{+∞} \frac{1}{n^{2}}

ⅰ

\sum_{n = 1}^{+∞} \frac{1}{n^{2}}

\frac{π^{2}}{6}

▶Result:

\frac{π^{2}}{6}

The numeric value of:

\frac{π^{2}}{6}

equals:

\frac{{\approx 3.1416}^{2}}{6}

\frac{\approx 9.8696}{6}

▷

\approx 1.6449