tangent of f(x)=1/x at x=-2
Check the domain before calculating the tangent:
Find the tangent at
To ease differentiation, the expression is turned into
Let's perform the differentiation:
Apply the differentiation rule: with f =
ⓘ The derivative of x^n is n*x^(n-1): =
ⓘ Multiplying by -1 gives the opposite: =
ⓘ The factor is moved to the numerator or the denominator by changing the sign of its exponent, for a nonzero base: =
Compute f()
ⓘ The sign of a fraction goes in front of the bar, whether it comes from the numerator or the denominator: =
The point of tangency is (, )
Compute f'()
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: = =
The slope is f'() =
The tangent passes through this point with this slope:
Compute the y-intercept:
ⓘ Multiplying a fraction by a number multiplies its numerator: = = ■To add fractions, put them over the same denominator, then add the numerators. We choose , the least common multiple of and . Multiplying the numerator and the denominator by the same number does not change the fraction: = =
ⓘ Multiplications are done before additions and subtractions: =
ⓘ The numerator and the denominator are computed before the division: =
ⓘ We simplify the fraction by dividing the numerator and the denominator by , their greatest common divisor: =
ⓘ Multiplying a fraction by a term multiplies its numerator: = =
▶Tangent line: