tangent of y=x+sqrt(x),(49,56)
Find the tangent at
Let's differentiate:
ⓘ The derivative of a sum is the sum of the derivatives: =
ⓘ The derivative of sqrt(x) is 1/(2*sqrt(x)): =
Compute f()
ⓘ The square root of a number is the positive number whose square is that number: = ; =
ⓘ Start from and move forward on the number line: =
The point of tangency is (, )
Compute f'()
ⓘ The square root of a number is the positive number whose square is that number: = ; =
ⅰ =
ⓘ To add fractions, put them over the same denominator, then add the numerators: =
ⓘ The numerator and the denominator are computed before the division: =
The slope is f'() =
The tangent passes through this point with this slope:
Compute the y-intercept:
ⓘ Multiplying a fraction by a number multiplies its numerator: = =
ⓘ We simplify the fraction by dividing the numerator and the denominator by , their greatest common divisor: = =
ⓘ To add fractions, put them over the same denominator, then add the numerators: =
ⓘ Multiplications are done before additions and subtractions: = = = =
ⓘ The numerator and the denominator are computed before the division: =
ⓘ Multiplying a fraction by a term multiplies its numerator: = ■To add fractions, put them over the same denominator, then add the numerators: =
ⓘ Multiplications are done before additions and subtractions: =
▶Tangent line: