x/3+3=2x+10
1) Let's solve in ℝ: x3 + 3 = 2x + 10
2) Let's sum the fractions: x3 + 3 -2x -10 = 0
ⓘ Start from 3 and move back 10 on the number line, going below zero: 3 -10 = -7■Like terms are grouped by adding their coefficients: x3 -2x = -5x3
-5x3 -7 = 0
ⓘ To add fractions, put them over the same denominator, then add the numerators: -5x3 -7 = -5x -7·33
-5x -7·33 = 0
ⓘ Multiplications are done before additions and subtractions: 7·3 = 21■The minus sign is factored out, changing the sign of each term: -5x -21 = -(5x + 21)
-5x + 213 = 0
Let's solve in ℝ: -(5x + 21) = 0
ⓘ A minus sign before a parenthesis changes the sign of each of its terms: -(5x + 21) = -5x -21
-5x -21
-5x = 21
ⓘ Both sides are divided by -5
x = 21-5
ⓘ The sign of a fraction goes in front of the bar, whether it comes from the numerator or the denominator: 21-5 = -215
▶Solution found: x = -215
3) The numeric value of: x = -215 is:
▷ x = -4.2