x^2+7x-27=0
1) Let's solve in ℝ: x2 + 7x -27 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 1, b = 7 and c = -27
Δ = 72 -4·1·(-27)
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 72 = 7·7 = 49
Δ = 49 -4·(-27)
ⓘ Multiplications are done before additions and subtractions. Two minus signs cancel out, the product of two negative numbers is positive: -4·(-27) = 4·27 = 4·(20 + 7) = 4·20 + 4·7 = 80 + 28 = 108
Δ = 49 + 108
ⓘ Start from 49 and move forward 108 on the number line: 49 + 108 = 157
Δ = 157
As Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -7 -1572·1
x1 = -7 -1572
ⓘ The minus sign is factored out, changing the sign of each term: -7 -157 = -(7 + 157)
x1 = -7 + 1572
The quadratic formula gives x2 = -b + Δ2a = -7 + 1572·1
x2 = -7 + 1572
▶Solutions obtained: x = { -7 + 1572, 157 -72 }
2) The numeric value of: x = { -7 + 1572, 157 -72 } equals:
x = { ≈ -7 + 12.53002, ≈ 12.5300 -72 }
x = { ≈ -19.53002, ≈ 5.53002 }
▷ x = { ≈ -9.7650, ≈ 2.7650 }