sum(1/n^2, n=1, +inf) — solución paso a paso

Calculemos:

\sum_{n = 1}^{+∞} \frac{1}{n^{2}}

ⅰ

\sum_{n = 1}^{+∞} \frac{1}{n^{2}}

\frac{π^{2}}{6}

▶Resultado:

\frac{π^{2}}{6}

El valor numérico de:

\frac{π^{2}}{6}

vale:

\frac{{\approx 3,1416}^{2}}{6}

\frac{\approx 9,8696}{6}

▷

\approx 1,6449