factorise 2x^2+4x
Let's factor in <math><mi>ℝ</mi></math>: <math><mn>2</mn><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup><mo> + </mo><mn>4</mn><mi>x</mi></math>
You can write the expression in factored form: <math><mi>x</mi><mo>·</mo><mo>(</mo><mn>2</mn><mi>x</mi><mo> + </mo><mn>4</mn><mo>)</mo></math>
Let's factorize in <math><mi>ℝ</mi></math>: <math><mo>(</mo><mn>2</mn><mi>x</mi><mo> + </mo><mn>4</mn><mo>)</mo></math>
You can factorize this expression into: <math><mn>2</mn><mo>·</mo><mo>(</mo><mi>x</mi><mo> + </mo><mn>2</mn><mo>)</mo></math>
<u>Factor identified</u>: <math><mo>(</mo><mi>x</mi><mo> + </mo><mn>2</mn><mo>)</mo></math>

▷<b>Result: &nbsp; <math><mn>2</mn><mi>x</mi><mo>·</mo><mo>(</mo><mi>x</mi><mo> + </mo><mn>2</mn><mo>)</mo></math></b><span style='font-size:smaller'> &nbsp; &nbsp; (computation required 5 steps and 3 ms)</span>