Additionnons les fractions : 4x + x + 1x -5 4·(x -5) + (x + 1)·xx·(x -5) ℹ4·(x -5) = 4x -20‖(x + 1)·x = x2 + x (4x -20) + (x2 + x)x·(x -5) ℹ4x -20 + x2 + x = 5x -20 + x2 5x -20 + x2x·(x -5) ▷Réponse : x2 + 5x -20x·(x -5)