integrate 2x+3
Let's integrate: <math><mo>∫(</mo><mn>2</mn><mi>x</mi><mo> + </mo><mn>3</mn><mo>)dx</mo></math> <math><mo>∫(</mo><mn>2</mn><mi>x</mi><mo>)dx</mo><mo> + </mo><mo>∫(</mo><mn>3</mn><mo>)dx</mo></math> <math><mn>2</mn><mo>·</mo><mfrac><mrow><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup></mrow><mrow><mn>2</mn></mrow></mfrac><mo> + </mo><mn>3</mn><mi>x</mi></math> <math><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup><mo> + </mo><mn>3</mn><mi>x</mi></math> You can factorize this expression into: <math><mi>x</mi><mo>·</mo><mo>(</mo><mi>x</mi><mo> + </mo><mn>3</mn><mo>)</mo></math> Indefinite integrals are defined up to an additive constant <m>C</m>, so this yields: <math><mi>x</mi><mo>·</mo><mo>(</mo><mi>x</mi><mo> + </mo><mn>3</mn><mo>)</mo><mo> + </mo><mi>C</mi></math> ▷<b>Answer: <math><mi>x</mi><mo>·</mo><mo>(</mo><mi>x</mi><mo> + </mo><mn>3</mn><mo>)</mo><mo> + </mo><mi>C</mi></math></b><span style='font-size:smaller'>, with <m>C</m> being any constant (computation took 6 steps and 9 ms)</span>
