integrate x^2+1
Let's compute the integral: <math><mo>∫(</mo><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup><mo> + </mo><mn>1</mn><mo>)dx</mo></math>
 <math><mo>∫(</mo><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup><mo>)dx</mo><mo> + </mo><mo>∫(</mo><mn>1</mn><mo>)dx</mo></math>
 <math><mfrac><mrow><msup><mrow><mi>x</mi></mrow><mrow><mn>3</mn></mrow></msup></mrow><mrow><mn>3</mn></mrow></mfrac><mo> + </mo><mi>x</mi></math>
Indefinite integrals are defined up to an additive constant <m>C</m>, so this yields: <math><mfrac><mrow><msup><mrow><mi>x</mi></mrow><mrow><mn>3</mn></mrow></msup></mrow><mrow><mn>3</mn></mrow></mfrac><mo> + </mo><mi>x</mi><mo> + </mo><mi>C</mi></math>

▷<b>Result: &nbsp; <math><mfrac><mrow><msup><mrow><mi>x</mi></mrow><mrow><mn>3</mn></mrow></msup></mrow><mrow><mn>3</mn></mrow></mfrac><mo> + </mo><mi>x</mi><mo> + </mo><mi>C</mi></math></b><span style='font-size:smaller'>, where <m>C</m> is a constant &nbsp; &nbsp; (processing: 4 steps, 7 ms)</span>