integre 1/sqrt(x)
Let's compute the integral: <math><mo>∫(</mo><mfrac><mrow><mn>1</mn></mrow><mrow><msqrt><mi>x</mi></msqrt></mrow></mfrac><mo>)dx</mo></math> For the <u>math expression</u>: <math><mfrac><mrow><mn>1</mn></mrow><mrow><msqrt><mi>x</mi></msqrt></mrow></mfrac></math>, we know the derivative formula: <math><mo>(</mo><msup><mrow><mi>a</mi></mrow><mrow><mi>n</mi></mrow></msup><mo>)'</mo><mo> = </mo><mi>n</mi><mo>·</mo><msup><mrow><mi>a</mi></mrow><mrow><mo>(</mo><mi>n</mi><mo> -</mo><mn>1</mn><mo>)</mo></mrow></msup></math>, so we try differentiating with <m>^(m+1)</m> Let's perform the differentiation: <math><mo>(</mo><msup><mrow><mi>x</mi></mrow><mrow><mo>(</mo><mo>-</mo><mfrac><mrow><mn>1</mn></mrow><mrow><mn>2</mn></mrow></mfrac><mo> + </mo><mn>1</mn><mo>)</mo></mrow></msup><mo>)'</mo></math> <math><mo>(</mo><msup><mrow><mi>x</mi></mrow><mrow><mo>(</mo><mfrac><mrow><mo>-</mo><mn>1</mn><mo> + </mo><mn>2</mn></mrow><mrow><mn>2</mn></mrow></mfrac><mo>)</mo></mrow></msup><mo>)'</mo></math> <math><mo>(</mo><msqrt><mi>x</mi></msqrt><mo>)'</mo></math> <math><mfrac><mrow><mn>1</mn></mrow><mrow><mn>2</mn><msqrt><mi>x</mi></msqrt></mrow></mfrac></math> The computed derivative matches the original <u>math expression</u> up to a constant factor. Therefore, the integral is: <math><mn>2</mn><mo>·</mo><mfrac><mrow><mn>1</mn></mrow><mrow><msup><mrow><mi>x</mi></mrow><mrow><mo>-</mo><mfrac><mrow><mn>1</mn></mrow><mrow><mn>2</mn></mrow></mfrac></mrow></msup></mrow></mfrac></math> <math><mn>2</mn><msqrt><mi>x</mi></msqrt></math> Indefinite integrals are defined up to an additive constant <m>C</m>, so this yields: <math><mn>2</mn><msqrt><mi>x</mi></msqrt><mo> + </mo><mi>C</mi></math> ▷<b>Answer: <math><mn>2</mn><msqrt><mi>x</mi></msqrt><mo> + </mo><mi>C</mi></math></b><span style='font-size:smaller'>, where <m>C</m> is a constant (computation required 10 steps and 2 ms)</span>
