integre x+1
Let's integrate: <math><mo>∫(</mo><mi>x</mi><mo> + </mo><mn>1</mn><mo>)dx</mo></math> <math><mo>∫(</mo><mi>x</mi><mo>)dx</mo><mo> + </mo><mo>∫(</mo><mn>1</mn><mo>)dx</mo></math> <math><mfrac><mrow><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup></mrow><mrow><mn>2</mn></mrow></mfrac><mo> + </mo><mi>x</mi></math> Indefinite integrals are defined up to an additive constant <m>C</m>, so this yields: <math><mfrac><mrow><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup></mrow><mrow><mn>2</mn></mrow></mfrac><mo> + </mo><mi>x</mi><mo> + </mo><mi>C</mi></math> ▷<b>Answer: <math><mfrac><mrow><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup></mrow><mrow><mn>2</mn></mrow></mfrac><mo> + </mo><mi>x</mi><mo> + </mo><mi>C</mi></math></b><span style='font-size:smaller'>, where <m>C</m> is a constant (computation took 4 steps and 7 ms)</span>
