limite x->0+ ln(x)
Let's evaluate the limit of <math><mi>ln</mi><mo>(</mo><mi>x</mi><mo>)</mo></math> when <m><math><mi>x</mi><mo> → </mo><mn>0</mn></math>⁺</m> So the limit of <math><mi>ln</mi><mo>(</mo><mi>x</mi><mo>)</mo></math> is <m><math><mi>-∞</mi></math></m> when <m><math><mi>x</mi><mo> → </mo><mn>0</mn></math>⁺</m> ▷<b>Answer: <math><mi>-∞</mi></math></b><span style='font-size:smaller'> (processing: 2 steps, 1 ms)</span>
