Compute the limit of <math><mfrac><mrow><mn>1</mn></mrow><mrow><mi>x</mi></mrow></mfrac></math> as <m><math><mi>x</mi><mo> → </mo><mi>+∞</mi></math></m>
So the limit of <math><mfrac><mrow><mn>1</mn></mrow><mrow><mi>x</mi></mrow></mfrac></math> is <m><math><mn>0</mn></math>⁺</m> when <m><math><mi>x</mi><mo> → </mo><mi>+∞</mi></math></m>

▷<b>Answer: &nbsp; <math><mn>0</mn></math></b><span style='font-size:smaller'> &nbsp; &nbsp; (computation required 2 steps and 2 ms)</span>