simplify (2x^2+4x)/2x
Let's simplify: <math><mfrac><mrow><mn>2</mn><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup><mo> + </mo><mn>4</mn><mi>x</mi></mrow><mrow><mn>2</mn><mi>x</mi></mrow></mfrac></math>
We first try to factorize the numerator
Let's factor in <math><mi>ℝ</mi></math>: <math><mn>2</mn><msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow></msup><mo> + </mo><mn>4</mn><mi>x</mi></math>
This expression can be factorized into: <math><mi>x</mi><mo>·</mo><mo>(</mo><mn>2</mn><mi>x</mi><mo> + </mo><mn>4</mn><mo>)</mo></math>
Let's factor in <math><mi>ℝ</mi></math>: <math><mo>(</mo><mn>2</mn><mi>x</mi><mo> + </mo><mn>4</mn><mo>)</mo></math>
You can factorize this expression into: <math><mn>2</mn><mo>·</mo><mo>(</mo><mi>x</mi><mo> + </mo><mn>2</mn><mo>)</mo></math>
<u>Factor identified</u>: <math><mo>(</mo><mi>x</mi><mo> + </mo><mn>2</mn><mo>)</mo></math>
With the new factorized numerator, we try to simplify the new quotient: <math><mfrac><mrow><mn>2</mn><mi>x</mi><mo>·</mo><mo>(</mo><mi>x</mi><mo> + </mo><mn>2</mn><mo>)</mo></mrow><mrow><mi>x</mi></mrow></mfrac></math>
 <math><mfrac><mrow><mn>2</mn><mo>·</mo><mo>(</mo><mi>x</mi><mo> + </mo><mn>2</mn><mo>)</mo></mrow><mrow><mn>2</mn></mrow></mfrac></math>

▷<b>Result: &nbsp; <math><mi>x</mi><mo> + </mo><mn>2</mn></math></b><span style='font-size:smaller'> &nbsp; &nbsp; (processing: 9 steps, 3 ms)</span>