Let's solve in ℝ: 16 + x + 23 = 1 1 + 2·(x + 2)6 = 1 1 + 2·(x + 2) = 6 1 + (2x + 4) = 6 5 + 2x = 6 2x = 6 -5 2x = 1 ▶Solution obtained: x = 12 The numeric value of: x = 12 is: ▷ x = 0.5