Let's solve in ℝ: 24·(x -1) = -6·(4 -x) + 18x 24·(x -1) + 6·(4 -x) -18x = 0 ℹ24·(x -1) = 24x -24‖6·(4 -x) = 24 + 6·(-x) (24x -24) + (24 + 6·(-x)) -18x = 0 ℹ-24 + 24 = 0‖24x -18x = 6x 6x + 0 -6x = 0 0 = 0 ▶Solution obtained: x ∈ ℝ