2x-5=2-(x-4)/3 — step-by-step solution

Let's solve in

ℝ

2 x - 5 = 2 - \frac{x - 4}{3}

2 x - 5 = \frac{3 \cdot 2 - (x - 4)}{3}

ℹ

- (x - 4)

- x + 4

‖

3 \cdot 2

6

2 x - 5 = \frac{6 - x + 4}{3}

2 x - 5 = \frac{10 - x}{3}

Let's add fractions:

2 x - 5 - \frac{10 - x}{3} = 0

\frac{3 \cdot 2 x - (10 - x)}{3} - 5 = 0

ℹ

3 \cdot 2

6

‖

- (10 - x)

- 10 + x

‖

\frac{6 x - 10 + x}{3} - 5

\frac{(6 x - 10 + x) - 5 \cdot 3}{3}

\frac{(6 x - 10 + x) - 5 \cdot 3}{3} = 0

ℹ

6 x + x

7 x

‖

-5 \cdot 3

-15

\frac{7 x - 10 - 15}{3} = 0

\frac{7 x - 25}{3} = 0

Let's solve in

ℝ

7 x - 25 = 0

7 x = 25

▶Solution obtained:

x = \frac{25}{7}

The numeric value of:

x = \frac{25}{7}

is:

▷

x = \approx 3.5714