4x^2+x+5=0 — step-by-step solution

⚠ 4x is read as the product 4*x: for a power, write 4^x

Let's solve in

ℝ

4 x^{2} + x + 5 = 0

Given the quadratic form

a x^{2} + b x + c

, let's compute the discriminant:

Δ = b^{2} - 4 a c

Δ = 1 - 4 \cdot 4 \cdot 5

Δ = 1 - 16 \cdot 5

Δ = 1 - 80

Δ = -79

Since

Δ < 0

, the equation has no solution.

Could not solve in

ℝ

for:

x

▶Solution:

x \in \emptyset