What is the 32nd decimal of square root of 2 over square root of 3?

The numeric value of:

\frac{\sqrt{2}}{\sqrt{3}}

is:

\frac{\approx 1.4142135623730950488016887242096981}{\approx 1.7320508075688772935274463415058724}

\approx 0.8164965809277260327324280249019638

▶So the 32nd decimal of $\frac{\sqrt{2}}{\sqrt{3}}$ is $6$

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