X^2=-4-4600*0.1*(X+2)
1) Let's solve in ℝ: X2 = -4 -4600·0.1·(X + 2)
X2 = -4 -460·(X + 2)
X2 + 4 + 460·(X + 2) = 0
X2 + 4 + (460X + 920) = 0
X2 + 924 + 460X = 0
Given the quadratic form ax2 + bx + c, let's compute the discriminant: Δ = b2 -4ac
Δ = 4602 -4·1·924
Δ = 211600 -4·924
Δ = 211600 -3696
Δ = 207904
As Δ > 0, the equation has two solutions:
For the first solution, we obtain: -b -Δ2a
X1 = -460 -2079042
X1 = -460 + 4·129942
X1 = -(230 + 2·12994)
X1 = -230 -2·12994
For the second solution, we obtain: -b + Δ2a
X2 = -460 + 2079042
X2 = -460 + 4·129942
X2 = -230 + 2·12994
Solution found: X = -2·12994 -230
Solution found: X = 2·12994 -230
▶Solution:   X = { -2·12994 -230, 2·12994 -230 }
2) The numeric value of: X = { -2·12994 -230, 2·12994 -230 } equals:
X = { -2·≈ 113.9912 -230, 2·≈ 113.9912 -230 }
X = { -≈ 227.9825 -230, ≈ 227.9825 -230 }
▷ X = { ≈ -457.9825, ≈ -2.0175 }