calculate arcsinh(1)

Let's evaluate: arcsinh(1)
Use the logarithmic form: arcsinh(t) = ln(t + t2 + 1)
ⅰ arcsinh(1) = ln(1 + 1 + 1)
ln(1 + 1 + 1)
ⓘ Parentheses are computed first: 1 + 1 = 2
▶Result:   ln(1 + 2)
The numeric value of: ln(1 + 2) equals:
ln(1 + ≈ 1.4142)
ln(≈ 2.4142)
▷ ≈ 0.8814

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