derivative of (tan^2(x)/(tan(x^2)))
⚠Ⓘ sin^n(u), cos^n(u) and tan^n(u) are read as powers of the function value: write (sin(u))^n, (cos(u))^n or (tan(u))^n
1) Let's differentiate: ddx(tan(x)2tan(x2))
We differentiate u1 = tan(x)2 and v2 = tan(x2) using: ddx(u1v2) = ddx(u1)·v2 -u1·ddx(v2)v22
2) Let's perform the differentiation u1: ddx(tan(x)2)
Apply the differentiation rule: ddx(fn) = n·ddx(f)·f(n -1) with f = tan(x)
2·ddx(tan(x))·tan(x)
2·1cos(x)2·tan(x)
2·tan(x)cos(x)2
3) Let's differentiate v2: ddx(tan(x2))
We differentiate using: ddx(tan(f)) = ddx(f)·1cos(f)2 (where f = x2)
ddx(x2)·1cos(x2)2
2xcos(x2)2
4) Let's evaluate the resulting derivative (u1v2)': 2·tan(x)cos(x)2·tan(x2) -tan(x)2·2xcos(x2)2tan(x2)2
2·tan(x)·tan(x2)·cos(x2)2 -tan(x)2·2x·cos(x)2cos(x)2·cos(x2)2tan(x2)2
2·tan(x)·tan(x2)·cos(x2)2 -sin(x)2·2xcos(x)2·cos(x2)2tan(x2)2
2·tan(x)·tan(x2)·cos(x2)2 -sin(x)2·2xcos(x)2·cos(x2)2·1tan(x2)2
2·tan(x)·tan(x2)·cos(x2)2 -sin(x)2·2xcos(x)2·cos(x2)2·tan(x2)2
2·tan(x)·tan(x2)·cos(x2)2 -sin(x)2·2xcos(x)2·sin(x2)2
▶Derivative:   2·cos(x2)2·tan(x)·tan(x2) -2x·sin(x)2cos(x)2·sin(x2)2