Let's perform the differentiation: (1 -x2)' Apply the differentiation rule: (f)' = (f)'·12f with f = 1 -x2 (1 -x2)'·12·1 -x2 ℹ(1 -x2)'·12·1 -x2 = (1 -x2)'2·1 -x2‖(1 -x2)' = 0 + (-x2)' 0 + (-x2)'2·1 -x2 -2x2·1 -x2 ▶Derivative: -x1 -x2