diff(4x+cos(x))

Let's perform the differentiation: ddx(4x + cos(x))
ⓘ The derivative of a sum is the sum of the derivatives: ddx(4x + cos(x)) = ddx(4x) + ddx(cos(x))
ddx(4x) + ddx(cos(x))
ⓘ The derivative of a constant multiple keeps that factor: that of ku is k·u': ddx(4x) = 4■The derivative of cos(x) is -sin(x): ddx(cos(x)) = -sin(x)
▶Derivative:   4 -sin(x)

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