distance (1,3),(3,1) — step-by-step solution

The distance is the norm of the vector joining the two points: subtract the coordinates, then take the square root of the sum of their squares

Let's calculate:

norm (coord (3, 1) - coord (1, 3))

norm (coord (3 - 1, 1 - 3))

ℹ

3 - 1

2

‖

1 - 3

-2

norm (coord (2, -2))

\sqrt{2^{2} + {(-2)}^{2}}

ℹ

2^{2}

4

‖

{(-2)}^{2}

4

\sqrt{4 + 4}

\sqrt{8}

▶Distance:

2 \times \sqrt{2}

The numeric value of:

2 \times \sqrt{2}

equals:

2 \times \approx 1.4142

▷

\approx 2.8284