domain(ln(x+y)-ln(x)-ln(y))

Let's find the domain of

\ln (x + y) - \ln (x) - \ln (y)

For the expression

\ln (x + y)

to be defined, we must have:

x + y > 0

For the expression

- \ln (x)

to be defined, we must have:

x > 0

For the expression

- \ln (y)

to be defined, we must have:

y > 0

The constraints

{x > 0, y > 0}

already imply

x + y > 0

: this condition can be removed

▶Domain of definition:

{x > 0, y > 0}

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