domain of (x+1)/(x-1) — step-by-step solution

Let's evaluate the domain of

\frac{x + 1}{x - 1}

For the expression

\frac{x + 1}{x - 1}

to exist, you must check:

x - 1 \neq 0

Solution found:

x \neq 1

▶Domain of definition:

x \in ℝ \ {1}