⚠ e^{x-2}<8 is read as e^(x-2)<8 Let's solve in ℝ: e(x -2) < 8 You can apply the ln function on both sides: ln(e(x -2)) < ln(8) ℹln(e(x -2)) = x -2‖ln(8) = 3·ln(2) x -2 < 3·ln(2) ▶Solution found: x < 3·ln(2) + 2 The numeric value of: x < 3·ln(2) + 2 equals: x < 3·≈ 0.6931 + 2 x < ≈ 2.0794 + 2 ▷ x < ≈ 4.0794