integral of-4/x
Let's compute the integral: ∫(-4x)dx
∫(-4x)dx = -4·∫(1x)dx
We use ∫(1x)dx = ln(abs(x)). The absolute value covers both signs of the denominator, on any interval where x != 0
-4·ln(abs(x))
▶Indefinite integrals are defined up to an additive constant C, so this yields: -4·ln(abs(x)) + C