Let's compute the integral: ∫(-4x)dx ∫(-4x)dx = -4·∫(1x)dx We use ∫(1x)dx = ln(abs(x)). The absolute value covers both signs of the denominator, on any interval where x != 0 -4·ln(abs(x)) ▶Indefinite integrals are defined up to an additive constant C, so this yields: -4·ln(abs(x)) + C