We have: y = x5 -2 The slope 15 is nonzero: the function is bijective on ℝ ⇥Let's solve in ℝ: y = x5 -2 ⇥ y + 2 = x5 ⇥ 5·(y + 2) = x ⇥ x = 5·(y + 2) ⇥ x = 5y + 5·2 ▶Solution obtained: x = 5y + 10