inverse of f(x)= 1/5 x-2
We have: y = x5 -2
The slope 15 is nonzero: the function is bijective on ℝ
⇥Let's solve in ℝ: y = x5 -2
⇥ y + 2 = x5
⇥ 5·(y + 2) = x
⇥ x = 5·(y + 2)
⇥ x = 5y + 5·2
▶Solution obtained: x = 5y + 10