midpoint (-1/4 ,-1/7),(3/4 , 6/7) — step-by-step solution

Let's find the midpoint of the points

coord (- \frac{1}{4}, - \frac{1}{7})

and

coord (\frac{3}{4}, \frac{6}{7})

Each coordinate of the midpoint is the average of the corresponding coordinates of the two points: M = (A + B)/2

Let's calculate:

\frac{coord (- \frac{1}{4}, - \frac{1}{7}) + coord (\frac{3}{4}, \frac{6}{7})}{2}

\frac{coord (- \frac{1}{4} + \frac{3}{4}, - \frac{1}{7} + \frac{6}{7})}{2}

coord (\frac{- \frac{1}{4} + \frac{3}{4}}{2}, \frac{- \frac{1}{7} + \frac{6}{7}}{2})

ℹ

- \frac{1}{4} + \frac{3}{4}

\frac{- 1 + 3}{4}

‖

- \frac{1}{7} + \frac{6}{7}

\frac{- 1 + 6}{7}

coord (\frac{\frac{- 1 + 3}{4}}{2}, \frac{\frac{- 1 + 6}{7}}{2})

ℹ

- 1 + 3

2

‖

- 1 + 6

5

coord (\frac{\frac{2}{4}}{2}, \frac{\frac{5}{7}}{2})

coord (\frac{1}{2} \times \frac{1}{2}, \frac{5}{7} \times \frac{1}{2})

ℹ

\frac{1}{2} \times \frac{1}{2}

\frac{1}{4}

‖

\frac{5}{7} \times \frac{1}{2}

\frac{5}{14}

▶Midpoint:

coord (\frac{1}{4}, \frac{5}{14})

The numeric value of:

coord (\frac{1}{4}, \frac{5}{14})

is:

▷

coord (0.25, \approx 0.3571)