-9a^2-49a+516=0
1) Let's solve in ℝ: -9a2 -49a + 516 = 0
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac
Δ = (-49)2 -4·(-9)·516
ℹ(-49)2 = 2401‖-4·(-9) = 36
Δ = 2401 + 36·516
Δ = 2401 + 18576
Δ = 20977
As Δ > 0, the equation has two solutions:
For the 1st solution, we obtain: -b -Δ2a
a1 = 49 -209772·(-9)
a1 = 49 -20977-18
a1 = -49 -2097718
a1 = -49 + 2097718
For the second solution, we obtain: -b + Δ2a
a2 = 49 + 209772·(-9)
a2 = 49 + 20977-18
a2 = -49 + 2097718
Solution found: a = -20977 + 4918
Solution obtained: a = 20977 -4918
▶Solution:   a = { -20977 + 4918, 20977 -4918 }
2) The numeric value of: a = { -20977 + 4918, 20977 -4918 } is:
a = { -≈ 144.8344 + 4918, ≈ 144.8344 -4918 }
a = { -≈ 193.834418, ≈ 95.834418 }
▷ a = { ≈ -10.7686, ≈ 5.3241 }