(4x-3)^2=32 — step-by-step solution

⚠ 4x is read as the product 4*x: for a power, write 4^x

Let's solve in

ℝ

{(4 x - 3)}^{2} = 32

4 x - 3 = - 4 \cdot \sqrt{2}

4 x = - 4 \cdot \sqrt{2} + 3

Solution obtained:

x = \frac{3 - 4 \cdot \sqrt{2}}{4}

4 x - 3 = 4 \cdot \sqrt{2}

4 x = 4 \cdot \sqrt{2} + 3

Solution obtained:

x = \frac{4 \cdot \sqrt{2} + 3}{4}

▶Solution:

x = {\frac{3 - 4 \cdot \sqrt{2}}{4}, \frac{4 \cdot \sqrt{2} + 3}{4}}

The numeric value of:

x = {\frac{3 - 4 \cdot \sqrt{2}}{4}, \frac{4 \cdot \sqrt{2} + 3}{4}}

equals:

x = {\frac{3 - 4 \cdot \approx 1.4142}{4}, \frac{4 \cdot \approx 1.4142 + 3}{4}}

x = {\frac{3 - \approx 5.6569}{4}, \frac{\approx 5.6569 + 3}{4}}

x = {- \frac{\approx 2.6569}{4}, \frac{\approx 8.6569}{4}}

▷

x = {\approx -0.6642, \approx 2.1642}