(x+2)^2<= 25
Let's solve in ℝ: (x + 2)2 <= 25
(x + 2)2 -25 <= 0
This expression can be factorized into: ((x + 2) -5)·((x + 2) + 5)
Let's solve in ℝ: ((x + 2) -5)·((x + 2) + 5) <= 0
ℹ2 -5 = -3‖2 + 5 = 7
(x -3)·(x + 7)
Let's solve in ℝ: x -3 <= 0
Solution found: x <= 3
Let's solve in ℝ: x + 7 <= 0
Solution found: x <= -7
Let's build the table of the different terms to determine the global solution:
x-∞ -7 3 +∞
x -3--0+
x + 7-0++
(x + 2)2 <= 25+0-0+
▶Solution found: x ∈ [-7, 3]