Let's solve in ℝ: x + 3x -2 >= 0 Let's solve in ℝ: x + 3 >= 0 Solution obtained: x >= -3 Let's solve in ℝ: x -2 > 0 Solution found: x > 2 Let's create the table of the different solutions to find the overall solution: x-∞ -3 2 +∞x + 3-0++x -2--×+x + 3x -2+0-×+ ▶Solution obtained: x ∈ (-∞, -3] ∪ (2, +∞)