solve 7(x+1)+2>=6x+13

We solve in

ℝ

7 \cdot (x + 1) + 2 \geq 6 x + 13

ⓘ Expand using the distributive law, multiplying each term of the sum by the other factor:

7 \cdot (x + 1)

7 x + 7

7 x + 7 + 2 \geq 6 x + 13

ⓘ Start from

7

and move forward

2

on the number line:

7 + 2

9

7 x + 9 \geq 6 x + 13

ⓘ We subtract

9

from both sides■Start from

13

and move back

9

on the number line:

13 - 9

4

7 x \geq 6 x + 4

ⓘ We subtract

6 x

from both sides

7 x - 6 x \geq 4

ⓘ Like terms are grouped by adding their coefficients:

7 x - 6 x

x

▶Solution found:

x \geq 4

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