write 3+4*i in exponential form

Compute the polar representation of 3 + 4i as rexp(iθ), where r is the modulus and θ is an argument
The modulus of the complex number a + ib is a2 + b2 thus:
ⅰ mod(3 + 4i) = 32 + 42
32 + 42
ⓘ Powers are computed before multiplications, additions and subtractions. With a positive integer exponent, a power corresponds to a repeated product: 32 = 3×3 = 9, 42 = 4×4 = 16
9 + 16
ⓘ Start by calculating what is inside the parentheses: 9 + 16 = 25
25
ⓘ The square root of a nonnegative real is defined as the nonnegative number whose square gives that real number: 25 = 5 since 52 = 25
5
For nonzero a + ib, the argument is the directed angle from the positive real axis to the vector (a, b); depending on the signs of a and b, it equals 0, π, π2, -π2, atan(ba), atan(ba) + π or atan(ba) -π:
ⅰ arg(3 + 4i) = arctan(43)
arctan(43)
So the polar form is:
ⅰ polar(3 + 4i) = 5exp(i×arctan(43))
▶Result:   5exp(i×arctan(43))

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