x^2-10x+24>=0 — step-by-step solution

Let's solve in

ℝ

x^{2} - 10 x + 24 >= 0

You can rephrase the expression into:

{(x - 5)}^{2} - 1

{(x - 5)}^{2} - 1 >= 0

You can factorize this expression into:

((x - 5) - 1) \cdot ((x - 5) + 1)

Let's solve in

ℝ

((x - 5) - 1) \cdot ((x - 5) + 1) >= 0

ℹ

- 5 - 1

-6

‖

- 5 + 1

-4

(x - 6) \cdot (x - 4)

Let's solve in

ℝ

x - 6 >= 0

Solution found:

x >= 6

Let's solve in

ℝ

x - 4 >= 0

Solution obtained:

x >= 4

Let's build the table of the different terms to determine the global solution:

▶Solution obtained:

x \in (-∞, 4] \cup [6, +∞)