x/3 =(5x-9)/4-(x-1)/2
1) Résolvons dans ℝ : x3 = 5x -94 -x -12
x3 = 5x -94 + -x + 12
x3 = (5x -9) + 2·(-x + 1)4
x3 = 5x -9 + 2·(-x + 1)4
2) Additionnons les fractions : x3 -5x -9 + 2·(-x + 1)4 = 0
x·4 -(5x -9 + 2·(-x + 1))·33·4 = 0
x·4 -(5x -9 + 2·(-x + 1))·312 = 0
3) Résolvons dans ℝ : x·4 -(5x -9 + 2·(-x + 1))·3 = 0
ℹ2·(-x + 1) = 2·(-x) + 2‖-(5x -9 + (2·(-x) + 2))·3 = -(15x -27 + (2·(-x) + 2)·3)
x·4 -(15x -27 + (2·(-x) + 2)·3) = 0
x·4 -15x + 27 -(2·(-x) + 2)·3 = 0
ℹx·4 -15x = -11x‖-(-2x + 2) = 2x -2
-11x + 27 + (2x -2)·3 = 0
-11x + 27 + (6x -6) = 0
ℹ27 -6 = 21‖-11x + 6x = -5x
-5x + 21 = 0
-5x = -21
5x = 21
▶Solution trouvée : x = 215
4) La valeur numérique de : x = 215 vaut :
▷ x = 4.2