1) Résolvons dans ℝ : x3 = 5x -94 -x -12 x3 = 5x -94 + -x + 12 x3 = (5x -9) + 2·(-x + 1)4 x3 = 5x -9 + 2·(-x + 1)4 2) Additionnons les fractions : x3 -5x -9 + 2·(-x + 1)4 = 0 x·4 -(5x -9 + 2·(-x + 1))·33·4 = 0 x·4 -(5x -9 + 2·(-x + 1))·312 = 0 3) Résolvons dans ℝ : x·4 -(5x -9 + 2·(-x + 1))·3 = 0 ℹ2·(-x + 1) = 2·(-x) + 2‖-(5x -9 + (2·(-x) + 2))·3 = -(15x -27 + (2·(-x) + 2)·3) x·4 -(15x -27 + (2·(-x) + 2)·3) = 0 x·4 -15x + 27 -(2·(-x) + 2)·3 = 0 ℹx·4 -15x = -11x‖-(-2x + 2) = 2x -2 -11x + 27 + (2x -2)·3 = 0 -11x + 27 + (6x -6) = 0 ℹ27 -6 = 21‖-11x + 6x = -5x -5x + 21 = 0 -5x = -21 5x = 21 ▶Solution trouvée : x = 215 4) La valeur numérique de : x = 215 vaut : ▷ x = 4.2